First slide

Faraday's Laws

Question

An electrolytic cell contains alumina. If we have to obtain 50 g Al by using 105 A of current, the time required is

Easy

A

1.54 hr
B

2.15 hr
C

1 .42 hr
D

1.32 hr

Solution

${Al}^{3 +} + 3 e^{-} ⟶ Al$
Equivalent weight of $Al = \frac{27}{3} = 9$
From Faraday's first law, $w = zIt = \frac{E}{96500} It$
$∴ t = \frac{w \times 96500}{E \times I} = \frac{50 \times 96500}{9 \times 105} = 5105 .82 s = 1 .42 hr$

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