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An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons Reflected photon Incident photon be accelerated so that its wavelength becomes equal to 1.54 Ao:

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answer is 63.47.

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Detailed Solution

We know that 12mu2=eV and λ=hmu or u=hmλ or u2=h2m2λ2∴ 12m×h2m2λ2=e∨ or ∨=12m×h2m2λ2×e=12×h2mλ2×eSubstituting the values, we getV=12×6.625×10−3429.108×10−31×1.54×10−102×1.602×10−19=63.47volt

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An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons Reflected photon Incident photon be accelerated so that its wavelength becomes equal to 1.54 Ao: