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An electron is moving in Bohr's fourth orbit. Its de Broglie wavelength is λ. Then the circumference of the third orbit ?

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answer is 3.

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Detailed Solution

In 4th orbit, 2π(r0 × 42) = 4λ; λ = 8πr0 ....(1)circumference of third orbit in H-atom = 2πr= 2π(r0 × 32)= 18πr0...(2)Substituting (1) equation in (2) equation circumference of third orbit in H-atom = 18(λ/8)= 9/4 λ

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