An electron is moving with a kinetic energy of 4.55  ×  10−25. What will be de Broglie wavelength for this electron ?

KE=12 mv2 =4.55  ×  10−25V2=2 × 4.55  ×  10−259.1  ×  10−31 =1 ×  106V=103  m/sde  Broglie  wavelength  λ=hmv=6.626  ×  10−349.1  ×  10−31 ×  103=7.28×  10−7 m