Q.
An electron in 4th excited state of hydrogen atom de excites to first excited state in all possible ways. Number of Emission spectral lines observed will be
see full answer
Want to Fund your own JEE / NEET / Foundation preparation ??
Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya
a
10
b
15
c
6
d
3
answer is C.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Number of spectral lines=nn+12...where n=n2-n1;Fourth excited state=5th orbitFirst excited state=2nd orbit; n = 5-2 = 3; Number of spectral lines=3×42=6;
Watch 3-min video & get full concept clarity