Q.
Electronegativities of atoms A and B are 4.0 and 1.20 respectively. The percentage of ionic character of A - B bond is ___________
see full answer
Want to Fund your own JEE / NEET / Foundation preparation ??
Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya
answer is 72.24.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
% Ionic character =16χA−χB+3.5χA−χB2 xA=4.0xB=1.20% Ionic character =16(4.0−1.20)+3.5(4.0−1.20)2 =16(2.8)+3.5(2.8)2 =44.8+27.44 =72.24%
Watch 3-min video & get full concept clarity