Electrovalent or Ionic bond

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Question

Electronegativities of atoms A and B are 4.0 and 1.20 respectively. The percentage of ionic character of A - B bond is ___________

Moderate

Solution

$% Ionic character = 16 (χ_{A} - χ_{B}) + 3 .5 {(χ_{A} - χ_{B})}^{2}$
$\begin{array}{l} x_{A} = 4 .0 \\ x_{B} = 1 .20 \end{array}$
$\begin{array}{l} % Ionic character = 16 (4.0 - 1.20) + 3.5 (4.0 - 1.20)^{2} \\ = 16 (2.8) + 3.5 (2.8)^{2} \\ = 44.8 + 27.44 \\ = 72.24 % \end{array}$

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