First slide

Alkynes

Question

Electronegativity of carbon atoms depend upon their state of hybridization. In which of the following compounds, the carbon marked with asterisk is most electronegative?

Moderate

A

${CH}_{3} - \overset{*}{C} H_{2} - {CH}_{3}$
B

${CH}_{3} - \overset{*}{C} H = {CH}_{2}$
C

${CH}_{3} - \overset{*}{C} \equiv CH$
D

${CH}_{3} - \overset{*}{C} H_{3}$

Solution

[Step 1]:
Electronegativity of carbon atom depends on their state of hybridization. More S- character more the electronegativity.
[Step 2]:
$\underset{25 % S}{{SP}^{3}} < \underset{33 % S}{{SP}^{2}} < \underset{50 % S}{SP}$
[Step 3]:
Thus SP-carbon has highest electronegativity. i.e, option 3 is correct.

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