Electronegativity of carbon atoms depends upon their state of hybridization. In which of the following compounds, the carbon marked with asterisk (*) is the most electronegative?

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CH3−CH2−C*H2−CH3

CH3−C*H=C H−CH3

CH3−CH2-C≡C*H

CH3−CH2-CH=C*H2

answer is C.

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Detailed Solution

Electronegativity increases as the state of hybridization changes from sp3-sp2-sp. Thus, sp-carbon has the highest electronegativity.

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