Q.

The electronic configuration of four elements are : (I) [Xe]6s1                (II) [Xe]4f14,5d1,6s2             (III) [Ar] 4s2,4p5           (IV) [Ar]3d7,4s2Which one of the following statements about these elements is not correct?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

I is a strong reducing agent

b

II is a d-block element

c

III has high electron affinity

d

The compound formed between I and III is ionic

answer is B.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

[Xe]4f14,5d1,6s2 is not a d-block element. It is lutetium and is present in lanthanide series, so lutetium is a f-block element is (n−1)f1−14(n−1)s2p6d0−1ns2
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon