The electronic configuration of four elements are : (I) [Xe]6s1 (II) [Xe]4f14,5d1,6s2 (III) [Ar] 4s2,4p5 (IV) [Ar]3d7,4s2Which one of the following statements about these elements is not correct?
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a
I is a strong reducing agent
b
II is a d-block element
c
III has high electron affinity
d
The compound formed between I and III is ionic
answer is B.
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Detailed Solution
[Xe]4f14,5d1,6s2 is not a d-block element. It is lutetium and is present in lanthanide series, so lutetium is a f-block element is (n−1)f1−14(n−1)s2p6d0−1ns2