Q.

The electronic configuration of four elements are : (I) [Xe]6s1                (II) [Xe]4f14,5d1,6s2             (III) [Ar] 4s2,4p5           (IV) [Ar]3d7,4s2Which one of the following statements about these elements is not correct?

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a

I is a strong reducing agent

b

II is a d-block element

c

III has high electron affinity

d

The compound formed between I and III is ionic

answer is B.

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Detailed Solution

[Xe]4f14,5d1,6s2 is not a d-block element. It is lutetium and is present in lanthanide series, so lutetium is a f-block element is (n−1)f1−14(n−1)s2p6d0−1ns2
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