The electrons identified by quantum numbers n and l (i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n =3, l = 2 (iv) n = 3, l = 1 can be placed in order of increasing energy, from lowest to highest as
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
(iv) < (ii) < (iii) < (i)
b
(ii) < (iv) < (i) < (iii)
c
(i) < (iii) < (ii) < (iv)
d
(iii) < (i) < (iv) < (ii)
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Energy of n=3,l=1 < n=4,l=0 < n=3.l=2 < n=4,l=1n+l (3+1) (4+0) (3+2) (4+1)n = 3, l = 1 has lesser 'n' value than n = 4, l = 0n = 3, l = 2 has lesser 'n' value than n = 4, l = 1