An element (atomic mass 100 g/mol) having bcc structure has unit cell edge 400 pm. Then density of the element is

see full answer

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

10.376 g/cm3

2.144 g/cm3

7.289 g/cm3

5.188 g/cm3

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

ρ=n×Ma3×N0×10−30=2×100(400)3×6.02×1023×10−30= 5.188 g / cm3

Watch 3-min video & get full concept clarity