Element B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

Number of atoms per unit cell in ccp = N =4 Number of octahedral voids = N =4 A occupies half of the octahedral voids, thus A atoms per unit cell = 4/2 =2 Tetrahedral voids = 2 × N =8 So number of oxygen atoms = 8A:B:0:: 2:4:8Thus, structure of bimetallic oxide is AB2O4 .