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Q.

An element A in a compound ABD has oxidation number An-. It is oxidised by Cr2O72- in acid medium. In the experiment 1.68  × 10-3 moles of  K2Cr2O7  was used for 3.26  × 10-3 moles of ABD. The new oxidation number of A after oxidation is

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a

3

b

3-n

c

n-3

d

+n

answer is B.

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Detailed Solution

Meq. of K2Cr2O7  = Meq. of ABDn-factor of K2Cr2O7  in acidic medium = 66 × 1.68× 10-3 = x × 3.26 × 10-3  x = 3 ⇒   New oxidation state of A-n  will be =-n + 3
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An element A in a compound ABD has oxidation number An-. It is oxidised by Cr2O72- in acid medium. In the experiment 1.68  × 10-3 moles of  K2Cr2O7  was used for 3.26  × 10-3 moles of ABD. The new oxidation number of A after oxidation is