An element crystallises in fcc lattice having edge length 350 pm. Maximum radius of the atom which can be placed in the interstitial site without distorting the structure is
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a
58.55 pm
b
117 pm
c
51.23 pm
d
83 pm
answer is C.
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Detailed Solution
For fcc structure, (r+r-)=0.414 for octahedral void = 0.225 for tetrahedral void Thus, maximum packing can be octahedral void∴r+=0.414r-Also, r-=a22∴r+=0.414a22=0.414×35022=144.922=51.23pm