An element has an electronic configuration of 1s22s22p6 in its + 3 oxidation state. The formula of its sulphide is
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a
M3S2
b
MS2
c
MS3
d
M2S3
answer is D.
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Detailed Solution
Given M+3 has the configuration [Ne] then configuration of 'M' will be Ne3s23p1Valency of the element is ‘3’sulphide ion is S-2 Then formula of metal sulphide is M2S3