An element has electronic configuration 1s22s22p63s23p4 . Predict their period, group and block

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Period = 3rd, block = p, group = 16

Period = 5th, block = s, group = 1

Period = 3rd, block = p, group = 10

Period = 4th, block = d, group = 12

answer is A.

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Detailed Solution

Highest “n” value = periodSubshell in which last electron enters = blockGroup number = 10 + ns + np e¯s.

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