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An element with atomic mass 48 g / mol forms an fcc lattice.The edge length of lattice is 400 pm and observed density is 4.2 g/cm3. Fraction of occupied space is ________.

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answer is 0.84.

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Detailed Solution

Theoretical density = Z×Ma3×NA=4×48400×10−103×6.023×1023=4.98g/cm3% occupancy = observed density theoretical density ×1004.24.98=0.84

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An element with atomic mass 48 g / mol forms an fcc lattice.The edge length of lattice is 400 pm and observed density is 4.2 g/cm3. Fraction of occupied space is ________.