First slide

Classical atomic models

Question

An element with atomic number 16 has only one electron. Which orbit of it is equal in size to Ist orbit of H?

Moderate

Solution

$\begin{aligned} r_{1_{H}} = 0 .529 Å r_{n_{(A)}} = \frac{n^{2} \times 0 .529}{Z} = 0 .529 \\ n^{2} = z = 16 \\ n = 4 \end{aligned}$

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