First slide

Classical atomic models

Question

An element with atomic number 16 has only one electron. Which orbit of it is equal in size to I orbit of H?

Moderate

Solution

$\begin{aligned} r_{1_{H}} = 0 .529 Å r_{n_{(A)}} = \frac{n^{2} \times 0 .529}{Z} = 0 .529 \\ n^{2} = z = 16 \\ n = 4 \end{aligned}$

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