Q.

An element with molar mass 2.7×10−2kg  mol−1 forms a cubic unit cell with edge length 405 pm. If its density is 2.7×103kg  m−3, the radius of the element is approximately ______ ×10−12m(to the nearest integer).

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answer is 143.00.

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Detailed Solution

d=Z×MN×A⇒2.7×103=Z×2.7×10-26×1023×405×10-123Z=4⇒fcc  So 2a=4rr=2×4054=143.1675pm=143
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An element with molar mass 2.7×10−2kg  mol−1 forms a cubic unit cell with edge length 405 pm. If its density is 2.7×103kg  m−3, the radius of the element is approximately ______ ×10−12m(to the nearest integer).