First slide
Predicting position of element in modern periodic table
Question

An element with Z = 50 of modern periodic table belongs to same group as that of the element with Z= 

Moderate
Solution

Hints to predict the position of element in the Modern periodic table :

1)Elements from Z = 58-71……Lanthanoids…..4f series….6th period……3rd(IIIB) group;

2)Elements from Z = 90-103……Actinoids…..5f series….7th period……3rd(IIIB) group;

3)Elements from Z = 104-118………..Last two digits gives group number….. 7th period;

4)Elements from Z = 31-57….subtract 18 to get preceding element;

5)Elements from Z = 72-89….subtract 32 to get preceding element;

6)Elements from Z = 104-120….subtract 32 to get preceding element ;

For Z=104-120….simplest Hint

7)Elements from Z = 104-120….subtract 82 to get a lower member(Z<30) belonging to same group;

Hints 4, 5 and 6 can be used repeatedly until an element belonging to same group with Z < 30 is obtained;

Elements with Z < 30 with their group, period and block can be known from Electronic configuration;

Ex : Z=114, 82, 50, 32, 14, 6….belong to 14th(IVA) group;

(114-32)=82; (82-32)=50; (50-18)=32; (32-18)=14;

Z = 14…..Si….3s23p2…..n=3….3rd period……p-block….valence electrons(4)….14th group;

Z = 32…..Ge….4s24p2…..n=4….4th period……p-block….valence electrons(4)….14th group;

Z = 50…..Sn….5s25p2…..n=5….5th period……p-block….valence electrons(4)….14th group;

Z = 82…..Pb….6s26p2…..n=6….6th period……p-block….valence electrons(4)….14th group;

Z = 114…..Fl….7s27p2…..n=7….7th period……p-block….valence electrons(4)….14th group;

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