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An element, X has the following isotopic composition, 200X:90% 199X:8% 202X:2%The weighted average atomic mass of the naturally occurring element ‘X’ is closest to _____.

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answer is 200.

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Detailed Solution

Average atomic mass ofX=90100×200+8100×199+2100×202=199.96 amu ≈ 200 amu

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An element, X has the following isotopic composition, 200X:90% 199X:8% 202X:2%The weighted average atomic mass of the naturally occurring element ‘X’ is closest to _____.