Q.
An element X has the following isotopic composition.X 100:80%,102X:20%The weighted average atomic mass of the naturally occurring element X is closest to
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a
101.1 amu
b
100.4 amu
c
100.8 amu
d
101.8 amu
answer is B.
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Detailed Solution
Mavg =100×80+102×20100=100.4 amu
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