For the elementary reaction M→N the rate or disappearance of M increases by a factor of $$8$$ upon doubling the concentration of M. The order of the reaction with respect to M ts

Question

For the elementary reaction M→N the rate or disappearance of M increases by a factor of $$8$$ upon doubling the concentration of M. The order of the reaction with respect to M ts

Infinity Learn · Accepted Answer

For elementary reaction, M→NRate law can be written as rate ∝MnRate $$=kMn$$                                  ……$$(i)When$$ we double the concentration of [M], rate becomes $$8$$ times, hence, new rate law can be written as                           $$8$$× rate $$=k$$[$$2M$$]n⇒ Rate $$8$$× rate $$=k$$[M]nk[$$2M$$]n∴ $$18=1$$[$$2$$]n ⇒ $$2n=8=23$$⇒$$n=3$$

For the elementary reaction $M \to N$ the rate or disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M ts

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For the elementary reaction M→N the rate or disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M ts

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For the elementary reaction $M \to N$ the rate or disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M ts