Elevation in boiling point of a molar (1 M) glucose solution (d=1.2 g mL−1) is

Molarity = 1 M = 1 mol L-11000 mL of solution has glucose = 180 g(1000×1.2)g of solution has glucose = 180 g∴ Solute (w1)=180 gSolution = 1200 gSolvent, H2O(w2)=1200−180=1020g∴ΔTb=1000Kbw1m1w2               =1000×Kb×180180×1020       =0.98 Kb