Emf of the cell, Fes/Fe+20.01M//Ag+0.1M/Ags is equal to Ecell0=1.24 V

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1.18 V

1.24 V

1.12 V

1.30 V

answer is B.

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Detailed Solution

Cell reaction isFes+2Ag+0.1M→2eFe+20.01M+2Ags; Ecell=Ecell0 +0.0591n log PR; Ecell=Ecell0+0.05912 log 0.01M0.1M2; Ecell=Ecell0=1.24 V

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