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$EMF of cell Ni {Ni}^{2 +} (1 .0 M) ∥ {Au}^{3 +} (1 .0 M) Au is......., if E^{\circ} for$ ${Ni}^{2 +} ∣ Ni is - 0 .25 V, E^{\circ} for {Au}^{3 +} ∣ Au is 1 .50 V .$

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a

+1.255V

b

-1.75 V

c

+1.75 V

d

+4.0 V

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detailed solution

Correct option is C

Ecell=EOPNi/Ni22+∘+ERPAu3+/Au∘EORNi∘−0.0592log⁡Ni2++ERPAu∘+log⁡0.0593Au3+=0.25−0.0592log⁡(1.0)+1.50+0.0593log⁡1.0=1.75V

ctaimg

ctaimg

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The conductivity of a saturated solution of ${Ag}_{2} C_{2} O_{4}$ is $4 \times 10^{- 5} S c m^{- 1}$ at 25°C. Conductivity of water is $6 \times 10^{- 8} S c m^{- 1}$ . What is the approximate molar conductivity of $C_{2} O_{4}^{2 -}$ ion at infinite dilution, given molar conductivity of Ag+ ions at infinite dilution is $62 S c m^{2} / m o l$ and $K_{sp} ({Ag}_{2} C_{2} O_{4}) = 3 .2 \times 10^{- 11}$

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