Q.
Emf of a cell in terms of reduction potential of its left and right electrodes is:
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a
E=Eleft−Eright
b
E=Eleft+Eright
c
E=Eright−Eleft
d
E=−[Eright+Eleft]
answer is C.
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Detailed Solution
Ecell=EOPL+ERPREcell=−ERPL+ERPR
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