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An Intiative by Sri Chaitanya
a
0.00 V, −nFEcell0=−2.303RTlog10KC
b
1.00V, −nFEcell0=−2.303RTnFlog10KC
c
-1.00V, −nFEcell0=−2.303RTlog10KC
d
−nFEcell0=−2.303RTlog10KC
answer is A.
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