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Q.

Emf of the cell Zns/Zn+20.1M//Ag+0.01M/Ags is equal to EZn+2/Zn0=−0.76V; EAg+/Ag0=+0.8V

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Detailed Solution

Ecell0=Ecathode0−Eanode0Ecell0=+0.8V−−0.76VEcell0=1.56V;cell  reaction:Zns+2Ag+0.01M→Zn+20.1M+2AgsEcell =Ecell0−0.0591nlogPRZns=Ags=1Ecell=1.56−0.05912log0.10.012Ecell=1.56−0.0592log103Ecell=1.47V
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