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Emf of the cell Zn /Zn+2//Cu+2/Cu will be highest when

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answer is 2.

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Detailed Solution

Ecell = Ecello−0.0591nlog[Products]ReactantsAnode−Zn → Zn+2+2e−Cathode Cu+2 +2e-→Cu Zn + Cu+2 → Zn+2 +CuE0cell is a constantEcell∝ −logZn+2Cu+2Lesser theZn+2Cu+2,higher will be the Ecell∴ (2) is correct

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Emf of the cell Zn /Zn+2//Cu+2/Cu will be highest when