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\large {E^0}_{C{u^{2 + }}/Cu}\, = \, + 0.337\,V,\large {E^0}_{Z{n^{2 + }}/Zn}\, = \, - 0.762\,V, The EMF of the cell,  
    Zn | Zn2+ (0.1M) || Cu2+ (0.01M) | Cu is

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a
+1.099 V
b
– 1.099 V
c
+1.069 V
d
– 1.069 V

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detailed solution

Correct option is C

Metal electrode with High SRP is cathode and with low SRP is anodeCell reactionApplying Nernst equation

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