First slide

Nernst Equation

Question

The emf of a Daniel cell at 298K is E₁ Zn | ZnSO_4(0.01M) || CuSO_4(1.0M) | Cu when the concentration of ZnSO₄ is 0.1 M and that CuSO₄ is 0.01 M, the emf changed to E₂. What is the relationship between E₁ and E₂

Moderate

A

E₂=0 $\neq$ E₁
B

E₁ > E₂
C

E₁ < E₂
D

E₁ = E₂

Solution

As electrolyte concentration in anode compartment is decreased SOP of Zn electrode increases or SRP of Zn electrode decreases,and EMF of cell increases.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App