Q.

The emf of a Daniel cell at 298K is E1  Zn | ZnSO4(0.01M) || CuSO4(1.0M) | Cu  when the concentration of ZnSO4 is 0.1 M and that CuSO4 is 0.01 M, the emf changed to E2. What is the relationship between E1 and E2

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a

E2=0≠E1

b

E1 > E2

c

E1 < E2

d

E1 = E2

answer is B.

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Detailed Solution

As electrolyte concentration in anode compartment is decreased SOP of  Zn electrode increases or SRP  of Zn electrode decreases,and EMF of cell increases.
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