First slide

Standard EMF of a cell

Question

The EMF of the following cells are
Cu|Cu²⁺(1M) || Ag⁺ (1M) | Ag, E^o = 0.46 V
Zn | Zn²⁺ (1M) || Cu²⁺ (1M) | Cu, E^o = 1.10V
The EMF of the cell
Zn|Zn²⁺(1M)|| Ag⁺ (1M) | Ag will be

Moderate

Solution

$E_{cell}^o = E_c^o - E_a^o$

In 1st cell Cu electrode is anode and Ag electrode is cathode
$E_{A{g^ + }/Ag}^o - E_{C{u^{ + 2}}/Cu}^o = 0.46$
$E_{A{g^ + }/Ag}^o - 0.46 \;= E_{C{u^{ + 2}}/Cu}^o$
In 2nd cell Zn electrode is anode and Cu electrode is cathode.
$E_{C{u^{ + 2}}/Cu}^o - E_{Z{n^{ + 2}}/Zn}^o = 1.1$
$E_{A{g^ + }/Ag}^o - 0.46 - E_{Z{n^{ + 2}}/Zn}^o = 1.1$
In 3rd cell Zn electrode is anode and Ag electrode is cathode.
$E_{A{g^ + }/Ag}^o - E_{Z{n^{ + 2}}/Zn}^o = 1.1 + 0.46 = 1.56V$

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