First slide

Nernst Equation

Question

The e.m.f. of the given Daniel cell at 298 K is E₁ Zn /ZnSO₄(0.01M)//CuSO₄ (1.0M)/Cu When the concentration of ZnSO₄ is 1.0 M and that of CuSO₄ is 0.01M, the e.m.f. changed to E₂. What is the relationship between E₁ and E₂ ?

Moderate

A

E₁ > E₂
B

E₁ < E₂
C

E₁ = E₂
D

$\large {E_2}\, = \,0\, \ne \,{E_1}$

Solution

For metal electrode
$SOP\propto\frac{1}{[M^{+n}]_{anode}}$
$SRP\propto\;{[M^{+n}]_{cathode}}$
Electrolyte concentration in anode compartment decreases SOP increases.Electrolyte concentration in cathode compartment decreases SRP decreases.
E₁> E₂

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