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Q.

EN of the element A is E1, and IP is E2. Hence, EA will be

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a

2E1−E2

b

E1−E2

c

E1−2E2

d

E1+E2/2

answer is A.

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Detailed Solution

EN=IP+EA2⇒EA=2EN−IP=2E1−E2
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EN of the element A is E1, and IP is E2. Hence, EA will be