The energy of an electron in the first Bohr orbit of H atom is −13.6 eV .The possible total energy values(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

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− 3.4 eV

− 4.2 eV

− 6.8 eV

+6.8 eV

answer is A.

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Detailed Solution

Total energy=−13.6Z2n2eV . Put n=2,3,4 and get the value for subsequent orbits.

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