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Q.

The energy of an electron in the first Bohr’s orbit of a hydrogen atom is –2.18 × 10-18J. Its energy in the second orbit would be

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a

–1.09 × 10–18 J

b

–4.36 × 10–18 J

c

–5.45 × 10–19 J

d

–8.72 × 10–18 J

answer is C.

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Detailed Solution

En=-Z2n2E1given E1 =  - 2.18 × 10-18Jn = 2Z = 1E1=-12222.18×10-18J= -5.45 × 10-19J
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