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Q.

Energy of electron revolving in 2nd orbit of H- atom is -E1. Energy of electron revolving in 4th orbit of Be+3 ion is -E2. Ratio of magnitude of E1 to E2 is

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answer is 3.

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Detailed Solution

En=-Z2n2E1  - E1=energy  of  electron in  first  orbit  of  H− atom1  2nd  orbit  of  H−atom  .   .  . n=2; Z=12 4th  orbit  of  Be+3  ion .  .  .  n=4; Z=4;Magnitude ofE1:E2=1222:4242E1:E2=1:4
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