Energy of electron revolving in 2nd orbit of H- atom is -E1. Energy of electron revolving in 4th orbit of Be+3 ion is -E2. Ratio of magnitude of E1 to E2 is
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answer is 3.
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Detailed Solution
En=-Z2n2E1 - E1=energy of electron in first orbit of H− atom1 2nd orbit of H−atom . . . n=2; Z=12 4th orbit of Be+3 ion . . . n=4; Z=4;Magnitude ofE1:E2=1222:4242E1:E2=1:4