The energy required to melt 1g. ice is 33J. The number of quanta of radiation of frequency 4.67 × 1013 sec–1 that must be absorbed to melt 10g ice is

Energy required to melt one gram of ice = 33JEnergy required to melt ten grams of ice = 330JEnergy of each quanta = hv                                 = (6.625 × 10-34J.S)(4.67 × 1013s-1)                                 = (30.93 × 10-21 J)Total energy = Nhv (N = no. of quanta)Number of quanta,N= Total energy required to meltin grams of ice  Energy of each quanta                                N=33030.93×10-21 = 1.065 × 1022