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Q.

The energy of second Bohr orbit of hydrogen atom is −328 KJ mol−1, hence energy of fourth Bohr orbit would be

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a

−41 KJ mol−1

b

−82 KJ mol−1

c

−164 KJ mol−1

d

−1312 KJ mol−1

answer is B.

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Detailed Solution

E4E2=n22n42 E4=E2×n22n42 =328×416=82  KJ
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