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Q.

The energy of second orbit of hydrogen is equal to the energy of

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a

Fourth orbit of He+

b

Fourth orbit of Li2+

c

Second orbit of He+

d

Second orbit of Li2+

answer is A.

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Detailed Solution

E=−Z2n2 ×  13.6  eVE2=−13.64  for  'H'E=−Z2n2 ×  13.6  eV−13.64 =−Z2n2 ×  13.6Z2n2=14  Z=2,  n=4
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