The enthalpies of combustion of carbon and carbon monoxide are -390 kJ and -278 kJ respectively. The enthalpy of formation of CO in kJ is

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668

112

-112

-668

answer is C.

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Detailed Solution

C+O2 → CO2; ∆H=-290 kJ ...1 CO+12O2 → CO2; ∆H=-278 kJ ...2 By eq. (1) and eq. (2), we get C+12O2 → CO; ∆H=-112 kJ

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