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Q.

The enthalpies of combustion of carbon and carbon monoxide are -390 kJ  and -278 kJ respectively. The enthalpy of formation of CO in kJ is

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a

668

b

112

c

-112

d

-668

answer is C.

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Detailed Solution

C+O2 → CO2;    ∆H=-290 kJ            ...1 CO+12O2 → CO2;    ∆H=-278 kJ     ...2 By eq. (1) and eq. (2), we get C+12O2 → CO;    ∆H=-112 kJ
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