Enthalpy of CH4+12O2→CH3OH is negative.If enthalpy of combustion of CH4 and CH3OH is x and y respectively. Then which relation is correct ?

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x>y

x=y

None of these

answer is B.

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Detailed Solution

CH4+2O2→CO2+2H2O , ∆H=x ---(1) CH3OH+32O2→CO2+2H2O , ∆H=y ---(2) eq.(1)-eq(2)⇒CH4+12O2→CH3OH , ∆H=x-y Given ∆H=-ve , ∴x

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