Enthalpy of combustion of diamond is 395kJ/mole and Enthalpy of combustion of graphite is 393kJ/mole. Enthalpy change when one mole of graphite converts to one mole of diamond is
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a
2kJ
b
-2kJ
c
4kJ
d
-4kJ
answer is A.
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Detailed Solution
Combustion is always exothermic, ∆H=-ve; Cdiamond+O2g →CO2g; ∆H=-395kJ -I ; Cgraphite+ O2g →CO2g; ∆H=-393kJ -II; Eq II - Eq I Cgraphite→ Cdiamond; ∆H=+2kJ/mole
Enthalpy of combustion of diamond is 395kJ/mole and Enthalpy of combustion of graphite is 393kJ/mole. Enthalpy change when one mole of graphite converts to one mole of diamond is