The enthalpy of elements in their standard states is taken as zero. Hence the enthalpy of formation of a compound is
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a
always negative
b
always positive
c
positive (or) negative
d
equal to zero
answer is C.
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Detailed Solution
Consider following example ;Cs+O2g→CO2g,∆H=-393 kJ, ∆H=HP0-HR0; Since HR0 in this case is zero, ∆H=HP0=-393 kJ; Similarly for an endothermic process, ∆H=HP0=+ve ;