Q.

The enthalpy of fusion of Ice is 6.02 kJ mol-1. The heat capacity of  H2O is 4.18 J g−1K−1. What is the smallest number of ice cubes at 0°C, each containing one mole of  H2O ,that are needed to cool 500 g of liquid water from 20°C to 0°C?

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answer is 7.

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Detailed Solution

Heat released to cool 500 g water from 20°C to 0°C,          Q=msΔT=500×4.18×20=41,800 J=41.8 kJNumber of moles of water (Ice) that will melt to absorb 41.8 kJ=41.86.02=7Number of cubes of ice that will melt = 7.
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