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Q.

The enthalpy of Neutralisation of strong acids HA and weak acid HB by NaOH are -13.7 and -12.7 K.Caleq−1 .When one equivalent of NaOH is added of HA and HB, the enthalpy change was −13.5K.cal. In what ratio is the base distributed between HA and HB ?

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a

2:1

b

1:2

c

4:1

d

1:4

answer is C.

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Detailed Solution

Let the base be distributed between HA and HB in the following ratio a:ba+b=1----1 But given that HA+NaOH→H2O+NaA;ΔH=-13.7 K .cal HB+NaOH→H2O+NaB;ΔH=-12.7K.cala(-13.7)+b(-12.7)=-13.513.7a+12.7b=13.5---2 From 1 & 2 b=0.2 ; a=0.8ab=0.80.2=41( or )4:1
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