The enthalpy of neutralization of a weak monoprotic acid, HA in 1M solution with a strong base is -55.95KJ/mol. If the unionized acid requires 1.4 KJ/mol heat for its complete ionization and enthalpy of neutralization of the strong monobasic acid with a strong monoacidic base is -57.3 kJ/mol. Then % ionization of the weak acid in molar solution is
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a
1.2%
b
3.57%
c
6.07%
d
12.01%
answer is C.
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Detailed Solution
ΔH (neutralization) =ΔH (ionization) +ΔHrH++OH−→H2O−55.95=ΔH1−57.3−55.95=ΔHionisation=1.35 KJ/mol1.4 KJ/molheat is required for ionization so, % of heat utilized by 1 M acid for ionization =1.351.4×100 =96.43%So % of ionization =100-96.43 =3.57%