First slide

2nd Law of Thermodynaimcs

Question

Enthalpy of vapourisation for water is 186.5kJ mol^–1. The entropy change during vapourisation is __ kJK^–1mol^–1

Easy

Solution

$\Delta {S_{Vapourization}} = \frac{{\Delta {H_{Vap}}}}{{B.P}} = \frac{{186.5KJ}}{{373K}} = 0.5KJ/mole/K$

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